 # How to calculate the house edge “Any Craps” Bet

Online craps has a variety of betting, the player can play. However, not all bets have the same advantage to the house and the players. There are some bets are favorable to the player with less house edge, while other operations are the sucker bets that have higher house edges.
To maximize the chance of winning on each bet, you have to know the right criteria when selecting the best bets. To help you identify the right criteria, you must know how to calculate the house edge for craps. Off course, the calculation of the exact house edge can on any type of betting involve complicated compilation.

In a simple term, a house edge is the percentage of a bet, the casino will in the long run. This number is sometimes referred to as the casino advantage that a profit to a casino guaranteed. The higher the number, the less favorable is the bet for the player. If you want to stay with the maximum chance of winning at online craps, you should always bet on the bet with minimum house edge.

## Let’s betting the simple calculation of house edge for any crap:

The house edge calculation includes two important factors: the probability and payout. You need these two factors, know calculate the house edge for craps. In Craps, there are 11 results (2, 3, 4, 5, 6, 7, 8, 9, 10, 11 &amp; 12) are generated by the two dice, that can be achieved in 36 different ways. Suppose each craps 2, 3 and 12. A total of 2 can be achieved in a way, when the two dice you draw be a 1; Therefore to achieve with a probability 2 1/36. A total of 3 can be achieved in two ways, and can only be achieved in a total of 1 12. Therefore, each cube can be achieved in four ways, so that it has a probability of 4/36 or 1/9. The joint payoff for any crap bet is 7 in 1. This means that if you bet \$ 1 and any craps is rolled, you will win \$ 7, otherwise you will lose \$ 1.

With the probability and the payout are any known craps, the house edge for each bet craps can be calculated. In the long term bets in craps on any one player will win one and lose eight times because the probability of any craps is 1/9. In other words, if a player if he bets \$ 1 craps bet for 9 times, each time on any, he will win one time and get \$ 7 of casino and lose 8 times to the casino, which costs him \$ 8; he makes a net loss of \$ 1 to the casino. Therefore, the house edge would for any craps bet 1/9 be (win one, lose 8), when expressed as a percentage would be 11.11%.

You will know how the house edge for other bets in craps game, as “any seven” bet, which can be calculated in a similar manner, if you know how the house edge for each bet craps compile calculate.

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